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Splint

What's Wrong with This EL Code?

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I'm trying to code an EMA gradient indicator but it wont compile. Multicharts doesn't like the semicolon at the end of line 7 but I think that it should be there.

 

Also, I don't know how to plot the gradient in a subgraph. Is this the correct way to do it?

 

Inputs:Price( Close ),
Length( 100 ),
Displace( 0 ) ;

Variables: Gradient(0);	

Gradient=((MovAvgExponential(Price,Length,Displace)-(MovAvgExponential(Price,Length,Displace)[1])/2;

Plot1(Gradient);

Print(Gradient);

End;

 

Thanks

Splint

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I'm trying to code an EMA gradient indicator but it wont compile. Multicharts doesn't like the semicolon at the end of line 7 but I think that it should be there.

 

Also, I don't know how to plot the gradient in a subgraph. Is this the correct way to do it?

 

Inputs:Price( Close ),
Length( 100 ),
Displace( 0 ) ;

Variables: Gradient(0);	

Gradient=((MovAvgExponential(Price,Length,Displace)-(MovAvgExponential(Price,Length,Displace)[1])/2;

Plot1(Gradient);

Print(Gradient);

End;

 

Thanks

Splint

 

what is the error message?

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Hi Splint,

 

1. The 'end' command is used to terminate and exit a loop - there is no loop within your code so the final line can be removed.

 

2. The error on line 7 isn't really the semicolon at the end as your code editor (and mine!) suggests - it's the brackets. Count the '(' brackets and there are 5. Count the ')' brackets and there are only 3. The number of each type of bracket here needs to be equal before you can terminate the line with a semicolon.

 

3. One set of brackets on line 7 is redundant - there is no need to bracket everything to the right of the = sign, so you can lose the first bracket.

 

4. You can create a new variable representing the average to simplify line 7.

 

5. Depending on your desired outcome the Print command may not have been used correctly.

 

Here is your code with the basic issues corrected:

 

Inputs:
Price(c),
Length(100),
Displace(0) ;

Variables: 
Gradient(0);	

Gradient=((MovAvgExponential(Price,Length,Displace)-(MovAvgExponential(Price,Length,Displace)[1]))/2);

Plot1(Gradient);
Print(Gradient);

 

And here is your code with my additional suggestions and simplifications implemented:

 

Inputs:
Price(c),
Length(100),
Displace(0);

Variables: 
myAVG(0),
Gradient(0);

myAVG=MovAvgExponential(Price,Length,Displace);
Gradient=(myAVG-myAVG[1])/2;
Plot1(Gradient);
Print(Gradient);

 

Hope that helps!

 

BlueHorseshoe

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Thanks,

 

That was very helpful. I couldn't seem to get it to work with the exponential ma (didn't recognize the function) but I used the adaptive ma as shown and it seems to work. From what I understand the ama is a built-in function but the ema is not? I'd prefer to use an ema or even an sma. I assume there is a way of doing that?

 

 

Inputs:	Price( Close ),
	EffRatioLength( 100 ),
	FastAvgLength( 15 ), 
	SlowAvgLength(30);

Variables: 	Gradient(0),
	AMA(0);

AMA=AdaptiveMovAvg(Price,EffRatioLength,FastAvgLength,SlowAvgLength);
Gradient=(AMA-AMA[1])/2;

Plot1(Gradient);

Print(Gradient);

 

Thanks

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Thanks,

 

That was very helpful. I couldn't seem to get it to work with the exponential ma (didn't recognize the function) but I used the adaptive ma as shown and it seems to work. From what I understand the ama is a built-in function but the ema is not? I'd prefer to use an ema or even an sma. I assume there is a way of doing that?

 

 

Inputs:	Price( Close ),
	EffRatioLength( 100 ),
	FastAvgLength( 15 ), 
	SlowAvgLength(30);

Variables: 	Gradient(0),
	AMA(0);

AMA=AdaptiveMovAvg(Price,EffRatioLength,FastAvgLength,SlowAvgLength);
Gradient=(AMA-AMA[1])/2;

Plot1(Gradient);

Print(Gradient);

 

Thanks

 

Hi Splint,

 

Glad that helped!

 

I didn't want to mention that the EMA function you were attempting to call was unusual, as I assumed that the function must just have a different name within MultiCharts.

 

If it is the same as in TradeStation then it's as follows:

 

XAverage(NumericSeries,NumericSimple);

 

Or as a specific example:

 

XAverage(Close,20);

 

Note that there is no 'displace' input required - it's just the time series value and the length.

 

If you can't get it working with this information then try giving Tams a nudge to revisit the thread, as he/she is a MultiCharts user.

 

Regards,

 

BlueHorseshoe

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