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BlueHorseshoe

Getting A Value Out Of A Loop

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Hello,

 

I have a variable, X, the value for which is dependent on an input, N. I want to vary the input, and then return the input value that generates the maximum value for X.

 

I can obviously vary the input as follows:

 

For N=A to B begin . . . X= . . . End;

 

But for this range of N, how do I then return the value N that gives the maximum value for X?

 

Any help would be greatly appreciated.

 

BlueHorseshoe

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from my basic programming....

you need a simple 'compare' within the loop

 

eg;

MaxX=0

MaxNValue=0

 

for N=A to B begin

X=formula....

'Compare values and assign.....

if X>MaxX then 'this is only triggered at the start and if X>MaxX

MaxX=X

MaxNValue=N

end if

next N 'loop returns

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from my basic programming....

you need a simple 'compare' within the loop

 

eg;

MaxX=0

MaxNValue=0

 

for N=A to B begin

X=formula....

'Compare values and assign.....

if X>MaxX then 'this is only triggered at the start and if X>MaxX

MaxX=X

MaxNValue=N

end if

next N 'loop returns

 

Hi SIUYA,

 

This seems the obvious way, but unfortunately it doesn't seem to work in EasyLanguage. I am unable to suss out why, but basically it will return the first X greater than the initial MaxX or a MaxNValue equal to B . . . I tried moving the formula out to a seperate function, but it won't run a function with a variable input within a loop . . .

 

All very frustrating, but thanks for your help!

 

BlueHorseshoe

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I have no clue about easy language,only C,but have you tried putting the resulting values of X in an array over which you have a sort algo run afterwards and then have the largest value returned?

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Hello,

 

I have a variable, X, the value for which is dependent on an input, N. I want to vary the input, and then return the input value that generates the maximum value for X.

 

I can obviously vary the input as follows:

 

For N=A to B begin . . . X= . . . End;

 

But for this range of N, how do I then return the value N that gives the maximum value for X?

 

Any help would be greatly appreciated.

 

BlueHorseshoe

 

you have to be more explicit about what you want to do,

otherwise there is very little people can help.

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ditto Tams

like how many in N? if it's only two A and B then you don't need loop, etc.

 

pls post the code you developed from BHS' suggestion

(leaving out how you're getting X if it is proprietary...etc)

his 'logic' is sound so we may be just looking for a bug

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you have to be more explicit about what you want to do,

otherwise there is very little people can help.

 

ditto Tams

like how many in N? if it's only two A and B then you don't need loop, etc.

 

pls post the code you developed from BHS' suggestion

(leaving out how you're getting X if it is proprietary...etc)

his 'logic' is sound so we may be just looking for a bug

 

Here is the code, with a logic virtually identical to that suggested by SIUYA earlier in the thread:

 


MaxE=0;
MaxValue1=0;

For Value1=1 to 50 begin

If E>MaxE then
MaxE=E
Else
MaxE=MaxE;

If P<Value1 and P[1]>Value1 then begin
If M[1]=0 then
M=1
Else
M=M[1];
End
Else
M=M[1];

If P>Var2 and P[1]<Var2 then
M=0;

If M[1]=0 and M=1 then
B=C
Else
B=B[1];

If M[1]=1 and M=0 then
E=E[1]+(C-B)
Else
E=E[1];


If E>MaxE then
MaxValue1=Value1
Else
MaxValue1=MaxValue1;

End;

Plot1(MaxValue1);

 

As far as I can work out this should return the value for Value1 that is associated with the maximum value for E. What am I missing? Why doesn't this work?

 

I have been banging my head against a wall with this for several days now, so any help would be greatly appreciated.

 

Thanks,

 

BlueHorseshoe

 

ps As per ZDO's suggestion I have done this 'manually' with code for a handful of values and it works perfectly - but I want to be able to run a wide range of values without needing pages and pages of repetitive code.

Edited by BlueHorseshoe

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this might be totally useless as i dont know enough EL - but it looks like you will have an END in the wrong spot. :2c:

 

Yes, I'm guessing it's going to be something stupid like that and someone else will spot it instantly.

 

:doh:

 

BlueHorseshoe

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