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doitagainforme

Count Intersections (easylanguage)

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Hi all. Advice please. I draw a horizontal line on the closing price and continue to the right. How can I count the number of intersections of the price in the future?

 

variable: ID(0);
ID = TL_New(Date, Time, Close, Date, Time, Close);
Value1 = TL_SetExtRight (ID, True);

 

Thank!

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Hello,

 

I think how I would approach this would be to set up a variable that counts the number of bars since you began to plot the line, and then use this variable as the lookback period to inform a second variable, which increases by one each time price intersects with your line.

 

Someone else may suggest an easier approach though, so I'd stick around until you've had a few replies from more experienced programmers.

 

BlueHorseshoe

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Hi all. Advice please. I draw a horizontal line on the closing price and continue to the right. How can I count the number of intersections of the price in the future?

 

variable: ID(0);
ID = TL_New(Date, Time, Close, Date, Time, Close);
Value1 = TL_SetExtRight (ID, True);

 

Thank!

 

can you draw a diagram to illustrate your vision?

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input: count(3);
var: x(0), oldest(0), recycle(0), size(99);
array: id[99,3](0);  // 0=id, 1=price, 2=count, 3=age

once for x=0 to size begin
   id[x,0]=tl_new(d,t,0,d,t,0);
end;

if barstatus(1)=2 then begin
   oldest=0;
   for x=0 to size begin
       if L<=id[x,1] and H>=id[x,1] then begin
           id[x,2]=id[x,2]+1;
           if id[x,2]=count then begin
               id[x,1]=0;  id[x,2]=0;  id[x,3]=9999999;  tl_setend(id[x,0],d,t,0);  tl_setbegin(id[x,0],d,t,0);  // reset price, count and age
           end;
       end;
       if id[x,1]>0 then tl_setend(id[x,0],d,t,id[x,1]);
       id[x,3]=id[x,3]+1;
       if id[x,3]>oldest then begin
           oldest=id[x,3];  recycle=x;
       end;
   end;
   id[recycle,1]=c;  id[recycle,2]=0;  id[recycle,3]=0;  tl_setend(id[recycle,0],d,t,c);  tl_setbegin(id[recycle,0],d,t,c);
end;

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input: count(3);
var: x(0), oldest(0), recycle(0), size(99);
array: id[99,3](0);  // 0=id, 1=price, 2=count, 3=age

once for x=0 to size begin
   id[x,0]=tl_new(d,t,0,d,t,0);
end;

if barstatus(1)=2 then begin
   oldest=0;
   for x=0 to size begin
       if L<=id[x,1] and H>=id[x,1] then begin
           id[x,2]=id[x,2]+1;
           if id[x,2]=count then begin
               id[x,1]=0;  id[x,2]=0;  id[x,3]=9999999;  tl_setend(id[x,0],d,t,0);  tl_setbegin(id[x,0],d,t,0);  // reset price, count and age
           end;
       end;
       if id[x,1]>0 then tl_setend(id[x,0],d,t,id[x,1]);
       id[x,3]=id[x,3]+1;
       if id[x,3]>oldest then begin
           oldest=id[x,3];  recycle=x;
       end;
   end;
   id[recycle,1]=c;  id[recycle,2]=0;  id[recycle,3]=0;  tl_setend(id[recycle,0],d,t,c);  tl_setbegin(id[recycle,0],d,t,c);
end;

 

Thank you very much, works great, as would:applaud:

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